## Testing Cosmological Reciprocity

I have posted a few times about Etherington’s Reciprocity Theorem in cosmology, largely in connection with the Hubble constant tension – see, e.g., here.

The point is that if the Universe is described by a space-time with the Robertson-Walker Metric (which is the case if the Cosmological Principle applies in the framework of General Relativity) then angular diameter distances and luminosity distances can differ only by a factor of *(1+z) ^{2}* where

*z*is the redshift:

*D*.

_{L}=D_{A}(1+z)^{2}I’ve included here some slides from undergraduate course notes to add more detail to this if you’re interested:

The result *D _{L}=D_{A}(1+z)^{2}* is an example of Etherington’s Reciprocity Theorem and it does not depend on a particular energy-momentum tensor; the redshift of a source just depends on the scale factor when light is emitted and the scale factor when it is received, not how it evolves in between.

Etherington’s theorem requires light rays to be described by *null* geodesics which would not be the case if photons had mass, so introducing massive photons would violate the theorem. It also requires photon numbers to be conserved, so some mysterious way of making photons disappear might do the trick, so adding some exotic field that interacts with light in a peculiar way is another possibility, as is the possibility of having a space-time with torsion, i.e. a non-Riemannian space-time.

Another possibility you might think of is to abandon the Robertson-Walker metric. We know that the Universe is not exactly homogeneous and isotropic, so one could appeal to the gravitational lensing effect of lumpiness to provide a departure from the simple relationship given above. In fact a inhomogeneous cosmological model based on GR does not in itself violate Etherington’s theorem, but it means that the relation *D _{L}=D_{A}(1+z)^{2}* is no longer global. In such models there is no way of defining a global scale factor a(t) so the reciprocity relation applies only locally, in a different form for each source and observer. In order to test this idea one would have to have luminosity distances and angular diameter distances for each source. The most distant objects for which we have luminosity distance measures are supernovae, and we don’t usually have angular-diameter distances for them.

Anyway, these thoughts popped back into my head when I saw a new paper on the arXiv by Holanda et al, the abstract of which is here:

Here we have an example of a set of sources (galaxy clusters) for which we can estimate both luminosity and angular-diameter distances (the latter using gravitational lensing) and thus test the reciprocity relation (called the cosmic distance duality relation in the paper). The statistics aren’t great but the result is consistent with the standard theory, as are previous studies mentioned in the paper. So there’s no need yet to turn the Hubble tension into torsion!

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April 13, 2021 at 3:37 pm

I wonder if F. S. Lima is related to J. A. S. Lima? The latter Lima has written on similar topics before, and on various aspects of inhomogeneous universes, often with Santos and Busti as co-authors.

My paper in

The Open Journal of Astrophysicsreferences many of the latter Lima’s works.April 14, 2021 at 8:29 am

There is no relation between the two Limas. However, J. A. S. Lima was the doctoral supervisor of R. F. L. Holanda, who is first author on the paper linked to above.

April 13, 2021 at 7:32 pm

Is there a specific connection between violation of CCDR and torsion ? Or was that simply chosen to connect to previous comments with the more general point being that it might be early to use the excuse of `Hubble Tension’ to build new theories ?

April 13, 2021 at 9:33 pm

The most general non-Euclidean spaces include torsion which Riemannian spaces do not.

April 14, 2021 at 7:47 am

Right, but the question is whether that can lead to a violation of the CCDR?

April 14, 2021 at 10:11 am

Briefly, if the gravity is a metric theory and if the Maxwell equations are valid the recipricity relation is satisfied. If you have torsion then the Maxwell equations are modified so the tgeorem no longer applies.

April 14, 2021 at 4:53 pm

👍

April 14, 2021 at 4:52 pm

👍

April 16, 2021 at 1:50 am

“In such models there is no way of defining a global scale factor a(t) so the reciprocity relation applies only locally, in a different form for each source and observer. In order to test this idea one would have to have luminosity distances and angular diameter distances for each source.”

Probably naive question, but wouldn’t someone always test the DDR for each source separately? So not just for inhomogeneous models?

April 16, 2021 at 4:51 pm

It’s not normally possible to measure both luminosity distances and angular diameter distances for the same source. High-redshift supernovae, for example, furnish us with luminosity distances but can’t be resolved so there’s no hope of an angular diameter distance.

April 16, 2021 at 5:49 pm

Right. In an FRW universe, one could measure the luminosity distance for several objects at different redshift, and the angular-size distance for several objects at the same redshifts, and see if they are related as expected.

June 14, 2021 at 2:19 pm

[…] Among the useful things in it you will find this summary of the current ‘tension’ over the Hubble constant that I’ve posted about numerous times (e.g. here): […]